Chemistry · Electrochemistry
Given the following standard reduction half-cell potentials: MnO4- + 8H+ + 5e- → Mn2+ + 4H2O, E° = +1.51 V O2 + 4H+ + 4e- → 2H2O, E° = +1.223 V Will the permanganate ion (MnO4-) liberate O2 from water in the presence of an acid?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1No, because E°cell = -2.733 V
- 2Yes, because E°cell = +0.287 V✓
- 3No, because E°cell = -0.287 V
- 4Yes, because E°cell = +2.733 V
Correct answer
Yes, because E°cell = +0.287 V
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