Chemistry · Electrochemistry
Given the following standard electrode potentials: MnO4- + 8H+ + 5e- → Mn2+ + 4H2O; E° = +1.51 V Cl2(g) + 2e- → 2Cl-; E° = +1.36 V Cu2+ + 2e- → Cu; E° = +0.34 V Cr3+ + e- → Cr2+; E° = -0.50 V Al3+ + 3e- → Al; E° = -1.66 V Which of the following cells would give an E°cell value closest to +1.0 V?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Al(s) | Al3+(aq) || Cr3+(aq), Cr2+(aq) | Pt(s)
- 2Mn(s) | Mn2+(aq) || H+(aq) | H2(g) | Pt(s)
- 3Cu(s) | Cu2+(aq) || Cl2(g) | Cl-(aq) | Pt(s)✓
- 4Pt(s) | Cr2+(aq), Cr3+(aq) || MnO4-(aq), Mn2+(aq), H+(aq) | Pt(s)
Correct answer
Cu(s) | Cu2+(aq) || Cl2(g) | Cl-(aq) | Pt(s)
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