Mathematics · Differential Equations
Given the differential equation x2(d2y/dx2) + 2x(dy/dx) = log(x) with initial conditions y(1) = 0 and y'(1) = 0. The unique solution y(x) is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1y(x) = 1 - 1x + (log(x))22 + log(x)
- 2y(x) = 1 - 1x + (log(x))22 - log(x)✓
- 3y(x) = -1 + 1x + (log(x))22 - log(x)
- 4y(x) = 1 + 1x + (log(x))22 - log(x)
Correct answer
y(x) = 1 - 1x + (log(x))22 - log(x)
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