Mathematics · Calculus

For x > 1, if (2x)2y = 4e2x-2y, then (1 + loge 2x)2 dydx is equal to:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1x loge 2x - loge 2x✓
2x loge 2x
3loge 2x
4x loge 2x + loge 2x

Correct answer

x loge 2x - loge 2x

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For x > 1, if (2x)2y = 4e2x-2y, then (1 + loge 2x)2 dydx is equal to:

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For x > 1, if (2x)2y = 4e2x-2y, then (1 + loge 2x)2 dydx is equal to:

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