Mathematics · AC Circuits
For the impedance Z = 3 + j4 Ω, what is the value of admittance Y?
- 1Y = 0.12 − j0.16 S✓
- 2Y = 3 + j4 S
- 3Y = 0.12 + j0.16 S
- 4Y = 0 S
Correct answer
Y = 0.12 − j0.16 S
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