Physics · Optical Fibres
For light traveling from a core of higher refractive index to a cladding of lower refractive index, total internal reflection is possible. However, if an input specifies a step-index fiber with a core refractive index n1 = 1.25 and a cladding refractive index n2 = 1.42, light cannot guide via total internal reflection since n1 < n2. If the indices are inverted such that n1 (core) = 1.42 and n2 (cladding) = 1.25, calculate the critical angle θc at the core-cladding interface.
- 135.3°
- 261.7°✓
- 355.4°
- 461.6°
Correct answer
61.7°
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