Chemistry · Thermodynamics
For an ideal gas, the work done during reversible isothermal expansion can be calculated using the expression w = −nRT ln(Vf / Vi). A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversibly to ten times its original volume in two separate experiments. The expansions are carried out at 300 K and at 600 K respectively. Choose the correct option.
- 1Work done at 600 K is 20 times the work done at 300 K.
- 2Work done at 300 K is twice the work done at 600 K.
- 3Work done at 600 K is twice the work done at 300 K.✓
- 4Work done is equal in both cases.
Correct answer
Work done at 600 K is twice the work done at 300 K.
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Chemistry?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Thermodynamics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Chemistry · Thermodynamics