Physics · Analog Communication
For an analog multiplier with one signal input having a peak voltage of 5 mV and a frequency of 1200 kHz, and the other input having a peak voltage of 10 mV and a frequency of 1655 kHz, what is the output expression (assuming a multiplier scale factor of K = 1 V -1 )?
- 115 mV cos 2π (455 kHz) t + 15 mV cos 2π (2855 kHz) t
- 250 mV cos 2π (2855 kHz) t + 50 mV cos 2π (455 kHz) t
- 325 μV cos 2π (455 kHz) t - 25 μV cos 2π (2855 kHz) t✓
- 425 μV cos 2π (455 kHz) t + 50 mV cos 2π (455 kHz) t
Correct answer
25 μV cos 2π (455 kHz) t - 25 μV cos 2π (2855 kHz) t
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