Mathematics · Vector Algebra
For a triangle ABC, let vector p = BC, vector q = CA and vector r = BA. If |p| = 2√3, |q| = 2 and cos(θ) = 1√3, where θ is the angle between p and q, then |p × (q - 3r)|2 + 3|r|2 is equal to:
- 1200✓
- 2410
- 3220
- 4340
Correct answer
200
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