For a simple pendulum executing simple harmonic motion, the time period is given by T = 2π√Lg. What will be the nature of the graph plotted between length (L) on the y-axis and the square of the time period (T2) on the x-axis?

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Physics · Oscillations

For a simple pendulum executing simple harmonic motion, the time period is given by T = 2π√Lg. What will be the nature of the graph plotted between length (L) on the y-axis and the square of the time period (T2) on the x-axis?

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A straight line passing through the origin

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Answer 1

A straight line passing through the origin

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A parabola opening upwards

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A rectangular hyperbola

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A horizontal line parallel to the time period axis

For a simple pendulum executing simple harmonic motion, the time period is given by T = 2π√Lg. What will be the nature of the graph plotted between length (L) on the y-axis and the square of the time period (T2) on the x-axis?

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For a simple pendulum executing simple harmonic motion, the time period is given by T = 2π√Lg. What will be the nature of the graph plotted between length (L) on the y-axis and the square of the time period (T2) on the x-axis?

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