Chemistry · Chemical Kinetics
For a reversible first-order reaction A ⇌ B with forward rate constant k 1 and backward rate constant k -1 , let 'a' be the initial concentration of A, 'x' be the concentration of B at time t, and 'x e ' be the equilibrium concentration of B. The rate of reaction dx dt is given by:
- 1k 1 x e a (x e - x)
- 2k 1 a x e (x e - x)✓
- 3k 1 (x e - x)
- 4k 1 a x e (x e + x)
Correct answer
k 1 a x e (x e - x)
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