Chemistry · Chemical Kinetics
For a reaction, activation energy Ea = 0 and the rate constant at 200 K is 1.6 × 106 s−1. The rate constant at 400 K will be: [Given: Gas constant, R = 8.314 J K−1 mol−1]
- 11.6 × 106 s−1✓
- 23.2 × 106 s−1
- 31.6 × 103 s−1
- 43.2 × 104 s−1
Correct answer
1.6 × 106 s−1
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Chemistry?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Chemical Kinetics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Chemistry · Chemical Kinetics