Mathematics · Trigonometry
For 0° < θ < 90°, the expression [(&sin; θ - &cos; θ)(1 + &tan; θ + &cot; θ)(&csc;2 θ)] / (&sec;3 θ - &csc;3 θ) is equal to:
- 1&sin; θ &cos; θ✓
- 2&sin;2 θ
- 3&cos;2 θ
- 4&sec; θ &csc; θ
Correct answer
&sin; θ &cos; θ
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