Mathematics · Definite Integrals
For 0 < x < 1, ∫ [Tan-1(1 - x + x2) + Tan-1(1 - x)] dx =
- 1x Cot-1x + log √(1 + x2) + c✓
- 2x Tan-1x - log(1 + x2) + c
- 3x Cot-1x + 34 log(1 + x2) + c
- 4x Tan-1x - 34 log √(1 + x2) + c
Correct answer
x Cot-1x + log √(1 + x2) + c
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