Mathematics · Calculus

Find the value of the definite integral ∫1/√2-1/√2 [ ( x + 1x - 1 )2 + ( x - 1x + 1 )2 - 2 ]1/2 dx.

Verified Solution4 OptionsUpdated: October 2026👁️1 View

14 loge(3 + 2√2)
2loge 16✓
32 loge 16
4loge 4

Correct answer

loge 16

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Find the value of the definite integral ∫1/√2-1/√2 [ ( x + 1x - 1 )2 + ( x - 1x + 1 )2 - 2 ]1/2 dx.

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Find the value of the definite integral ∫1/√2-1/√2 [ ( x + 1x - 1 )2 + ( x - 1x + 1 )2 - 2 ]1/2 dx.

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