Mathematics · Differential Equations
Find the unique solution of the initial value problem given by the differential equation y''(x) = 0, subject to the conditions y(0) = 0 and y'(0) = 0.
- 1y(x) = 2x
- 2y(x) = x
- 3y(x) = 0✓
- 4y(x) = x22
Correct answer
y(x) = 0
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