Mathematics · Partial Differential Equations
Find the solution u(x, t) for the partial differential equation ∂u∂t + 2∂u∂x = 0, given the initial condition u(x, 0) = e-x2.
- 1u(x, t) = e(x + 2t)2
- 2u(x, t) = e(x - 2t)2
- 3u(x, t) = e-(x - 2t)2✓
- 4u(x, t) = e-(x + 2t)2
Correct answer
u(x, t) = e-(x - 2t)2
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