Mathematics · Differential Equations
Find the particular solution of the differential equation y' = x2y2, given y = -1 when x = 0.
- 1y = 1x3 - 3
- 2y = 3x3 + 3
- 3y = 1x3 + 3
- 4y = -3x3 + 3✓
Correct answer
y = -3x3 + 3
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