Mathematics · Coordinate Geometry
Find the equation of the circle whose centre lies on the y-axis and which passes through the origin and the point (2, 3).
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- 16x2 + 6y2 + 13y = 0
- 26x2 + 6y2 - 13y = 0
- 33x2 + 3y2 + 13y = 0
- 43x2 + 3y2 - 13y = 0✓
Correct answer
3x2 + 3y2 - 13y = 0
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