Chemistry · Chemical Thermodynamics
Find the enthalpy change for the following reaction: CH4 + Cl2 → CH3Cl + HCl Given bond enthalpies: C - H = 416.2 kJ/mol Cl - Cl = 242.7 kJ/mol C - Cl = 330.5 kJ/mol H - Cl = 430.9 kJ/mol
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1+100.0 kJ/mol
- 2-102.5 kJ/mol✓
- 3-100.0 kJ/mol
- 4+102.5 kJ/mol
Correct answer
-102.5 kJ/mol
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