Computer · Boolean Algebra
Find the complement of the Boolean function F1 = x(y̅z̅ + yz).
- 1F̅1 = x + (y + z)(y̅ + z̅)
- 2F̅1 = x̅(yz + y̅z̅)
- 3F̅1 = x̅ + (y + z)(y̅ + z̅)✓
- 4F̅1 = x̅(yz − y̅z̅)
Correct answer
F̅1 = x̅ + (y + z)(y̅ + z̅)
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