Mathematics · Indefinite Integration
Evaluate the integral: ∫ e -2x (tan 2x - 2 sec 2 2x tan 2x) dx =
- 1e -2x sec 2 2x + c
- 2- e -2x 2 [tan 2x - sec 2 2x] + c
- 3- e -2x 2 [sec 2 2x + tan 2x] + c✓
- 4e -2x tan 2x + c
Correct answer
- e -2x 2 [sec 2 2x + tan 2x] + c
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