Mathematics · Integral Calculus
Evaluate the integral: ∫ dx√(3x + 2) - √(3x + 1) (where C is an arbitrary constant)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 123 √(3x + 2) - 13 √(3x + 1) + C
- 23(3x + 2)3/2 - (3x + 1)3/2 + C
- 3(3x + 2)3/2 + (3x + 1)3/2 + C
- 429 {(3x + 2)3/2 + (3x + 1)3/2} + C✓
Correct answer
29 {(3x + 2)3/2 + (3x + 1)3/2} + C
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