Mathematics · Calculus
Evaluate the indefinite integral: ∫ sec-1√x dx
- 1x sec-1√x - log(1 + x) + c
- 2sec-1√x - tan-1√x + c
- 3x sec-1√x + 2√(x - 1) + c
- 4x sec-1√x - √(x - 1) + c✓
Correct answer
x sec-1√x - √(x - 1) + c
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