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Mathematics · Limits

Evaluate: limn→∞ 1n [sin(πn) + sin(2πn) + ... + sin(nπn)]

Verified Solution4 OptionsUpdated: October 2026

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12π✓
22
3π/2
41

Correct answer

2π

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Evaluate: limn→∞ 1n [sin(πn) + sin(2πn) + ... + sin(nπn)]

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