Mathematics · Probability and Combinatorics

Die A consists of numbers 1, 3, and 5 on three faces, and 0 is marked on the remaining three faces. On the second die B, the odd numbers 1, 3, and 5 are replaced by twice their values (2, 6, and 10), and the remaining three faces consist of 2, 4, and 6. Both dice are thrown together and the product of the numbers obtained is taken. If we list all possible outcomes, which product will be obtained exactly three times?