Mathematics · Partial Differential Equations
Consider the initial boundary value problem (IBVP): ut + ux = 2u, x > 0, t > 0 u(0, t) = 1 + sin(t), t > 0 u(x, 0) = excos(x), x > 0 If u is the solution of the IBVP, then what is the value of u(2π, π)u(π, 2π)?
- 1-e-π
- 2-eπ
- 3e-π
- 4eπ✓
Correct answer
eπ
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