Mathematics · Calculus & Optimization
Consider the function f(x) = x2 defined on the closed interval [0, 1]. The maximum value of f(x) on this interval occurs at:
- 1x = 1√2
- 2x = 1✓
- 3x = 0 where f'(x) = 0
- 4x = 12
Correct answer
x = 1
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