Mathematics · Quadratic Equations
Consider the following three quadratic equations: Equation I: ax2 - (b + 4)x + (d/c) + 25 = 0 Equation II: ny2 - (m + 2)y + 2t = 0 Equation III: uz2 - 2tz + e + 18 = 0 Given conditions: - a is the second lowest odd prime number. - b is a perfect square less than 40, and it is the highest value among all variables. - b is double of m. - m is six times the value of n. - d is equal to the square of a. - c is the smallest prime number. - The value of t is eight more than double of n. - u is a perfect square number, more than n and c but less than a. - t is 10 more than u. - The sum of u and e is 34. Compare the following quantities: Quantity I: The sum of the smallest roots of Equation I and Equation II Quantity II: The highest root of Equation III
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Quantity I ≥ Quantity II
- 2Quantity I = Quantity II or relation cannot be established
- 3Quantity II > Quantity I
- 4Quantity I > Quantity II✓
Correct answer
Quantity I > Quantity II
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