Electronics Engineering · 8086 Microprocessor
Consider the following 8086 assembly language program: MOV AX, BB11H MOV CX, 1122H ADD AX, CX HLT What will be the contents of the registers after execution?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1CX = CC33H
- 2AX = CC33H✓
- 3CX = BB11H
- 4AX = BB11H
Correct answer
AX = CC33H
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