Mathematics · Differential Equations
Consider the differential equation ex+y dydx = ex-y. What is the solution of this differential equation given initial condition y(0) = 0?
- 1y = ln(2x+1)
- 2y = ln(2x-1)
- 32y = ln(2x+1)✓
- 42y = ln(2x-1)
Correct answer
2y = ln(2x+1)
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