Computer · Control Systems - Routh-Hurwitz Criterion
Consider the closed-loop characteristic polynomial: Δ(s) = s4 + 2s3 + 4s2 + 8s + 2 = 0. Using the Routh-Hurwitz criterion, determine the system's stability.
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- 1Stable because all entries in the first column are strictly positive.
- 2Unstable, because after treating a zero first element with the ε-method, there are sign changes in the first column.✓
- 3Marginally stable because a complete row of zeros appears in the Routh array.
- 4Critically stable because the system has a pair of purely imaginary roots.
Correct answer
Unstable, because after treating a zero first element with the ε-method, there are sign changes in the first column.
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