Physics · Nuclear Physics
Consider radioactive decays A → B with decay constant λA, and B → C with decay constant λB. At any time t, the number of nuclides of B is given by (NB)t = λAλB - λA (NA)0 (e-λAt - e-λBt), where (NA)0 is the number of nuclides of A at t = 0. If (T1/2)B > (T1/2)A is:
- 1λBλB - λA
- 2λAλB
- 3λBλA
- 4λAλB - λA✓
Correct answer
λAλB - λA
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