Mathematics · Rotational Mechanics
Consider a thin circular ring of mass 1 kg and diameter 0.2 m. If it rotates at 10 rotations per second about an axis passing through its centre and perpendicular to its plane, the value of its angular momentum is:
- 10.200 kg m2/s
- 21.256 kg m2/s
- 30.400 kg m2/s
- 40.628 kg m2/s✓
Correct answer
0.628 kg m2/s
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