Physics · Quantum Mechanics
Consider a quantum particle of mass m and charge e moving in a two-dimensional potential given by: V(x, y) = k2(x - y)2 + k(x + y)2 The particle is also subject to an external electric field E = λ(i - j), where λ is a constant, and i and j correspond to unit vectors along x and y directions, respectively. Let E1 and E0 be the energies of the first excited state and ground state, respectively. What is the value of E1 - E0?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1↔ √2km✓
- 2↔ √2km + eλ2
- 33↔ √2km
- 43↔ √2km + eλ2
Correct answer
↔ √2km
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