Chemistry · States of Matter
Boyle's law at constant temperature (T) may be expressed in differential form as:
- 1(dPdV)T = K2V
- 2(dPdV)T = -KV
- 3(dPdV)T = -KV2✓
- 4(dPdV)T = KV
Correct answer
(dPdV)T = -KV2
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