Chemistry · Gaseous State
Boyle's law at constant temperature may be expressed in differential form as:
- 1(dPdV)T = kV
- 2(dPdV)T = -kV2✓
- 3(dPdV)T = -kV
- 4(dPdV)T = k2V
Correct answer
(dPdV)T = -kV2
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