Chemistry · Chemical Kinetics
At temperature T(K), the following equation is obtained for a first-order reaction: log(k/A) = -x/T The activation energy (Ea) for this reaction is equal to: (where R = gas constant)
- 112.303 × x × R
- 2x2.303 × R
- 32.303 × Rx
- 42.303 × x × R✓
Correct answer
2.303 × x × R
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Chemistry?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Chemical Kinetics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Chemistry · Chemical Kinetics