Physics · Gravitation
Assuming the earth is a uniform sphere of radius R, the variation in the value of acceleration due to gravity with respect to height (h << R) and with respect to depth d above and below the surface of earth are approximately: [g is the acceleration due to gravity on the surface of the earth.]
- 1g(1 - hR) and g(1 - 2dR) respectively
- 2g(1 - 2hR) and g(1 - dR) respectively✓
- 3g(1 - hR) and g(1 - dR) respectively
- 4g(1 - 2hR) and g(1 - 2dR) respectively
Correct answer
g(1 - 2hR) and g(1 - dR) respectively
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