Physics · Electromagnetism
Assume that the z = 0 plane is the interface between two linear and homogeneous dielectrics. The relative permittivities are εr = 5 for z > 0 and εr = 4 for z 0 is E1 = (3î - 5ĵ + 4k̂) kV/m. If there are no free charges on the interface, the electric field in the region z < 0 is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1E2 = (3î - 5ĵ + 5k̂) kV/m✓
- 2E2 = (3î - 5ĵ - 5k̂) kV/m
- 3E2 = (3î - 5ĵ + k̂) kV/m
- 4E2 = (34î - 54ĵ + k̂) kV/m
Correct answer
E2 = (3î - 5ĵ + 5k̂) kV/m
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