Physics · Network Analysis
Apply Kirchhoff's Current Law (KCL) to write the current equations at three nodes of a circuit where: At Node 1: Incoming current is 3 A, and outgoing currents are I 1 and I 2 . At Node 2: Incoming current is I 2 , and outgoing currents are I 3 and I 4 . At Node 3: Incoming current is I 4 and 5 A, and outgoing current is I 5 .
- 1I 1 + I 2 - 3 = 0; I 2 - I 3 = I 4 ; I 4 = I 5 + 5
- 2I 1 + I 2 - 3 = 0; I 2 - I 3 = I 4 ; I 4 = I 5 - 5✓
- 3I 1 + I 2 + 3 = 0; I 2 + I 3 = I 4 ; I 4 = I 5 - 5
- 4I 1 - I 2 - 3 = 0; I 2 + I 3 = I 4 = I 5 + 5
Correct answer
I 1 + I 2 - 3 = 0; I 2 - I 3 = I 4 ; I 4 = I 5 - 5
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Network Analysis?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Network Analysis