Physics · Electromagnetic Theory
An infinite straight wire lying along the z-axis carries a time-dependent current I(t) = 0 for t ≤ 0, and I(t) = I0 for t > 0. If the retarded vector potential at point P is given by A⃗(s,t) = μ0I02π ln(ct + √(ct)2 - s2s) ẑ, then the resulting electric field E⃗(s, t) is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1E⃗(s,t) = -μ0I0cπ√(ct)2 - s2 ẑ
- 2E⃗(s,t) = -μ0I0c4π√(ct)2 - s2 ẑ
- 3E⃗(s,t) = -μ0I0c2π√(ct)2 - s2 ẑ✓
- 4E⃗(s,t) = -μ0I0c√(ct)2 - s2 ẑ
Correct answer
E⃗(s,t) = -μ0I0c2π√(ct)2 - s2 ẑ
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