Chemistry · Enzyme Kinetics
An enzyme has Km = 2 mM and Vmax = 100 nmol/min. At substrate concentration [S] = 2 mM in the presence of a competitive inhibitor with Ki = 1 mM and inhibitor concentration [I] = 2 mM, the apparent Km (Kmapp) becomes:
- 18 mM
- 26 mM✓
- 34 mM
- 42 mM
Correct answer
6 mM
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