Physics · Work, Energy and Power
An elevator capable of carrying a maximum load of 1800 kg (elevator + passengers) is moving upwards with a constant speed of 2 m/s. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator (Take g = 10 m/s2).
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1400 W
- 2250 W
- 31200 W
- 444000 W✓
Correct answer
44000 W
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