Physics · Modern Physics
An electron of a hydrogen-like atom with atomic number Z = 4 jumps from the 4th energy state to the 2nd energy state. The energy released in this process will be: (Given Rch = 13.6 eV, where R is the Rydberg constant, c is the speed of light, and h is Planck's constant)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 140.8 eV✓
- 23.4 eV
- 310.5 eV
- 413.6 eV
Correct answer
40.8 eV
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