Physics · Work, Energy and Power
An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 m/s. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift is: (Take g = 10 m/s2)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 134500 W✓
- 220000 W
- 323000 W
- 423500 W
Correct answer
34500 W
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