Physics · Alternating Current
An alternating voltage source V(t) = V0 sin(ωt + φ0) is applied across different electrical circuits. Match the electrical load in List-I with its correct steady-state current response in List-II: List-I (Electrical Load) A. Pure resistor R B. Pure inductor L C. Pure capacitor C D. Series RL circuit List-II (Current Response)1. i(t) = V0R sin(ωt + φ0)2. i(t) = V0ωL sin(ωt + φ0 − 90°)3. i(t) = V0ωC sin(ωt + φ0 + 90°)4. i(t) = V0√(R2 + ω2L2) sin(ωt + φ0 − tan−1(ωLR))
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1A → 4, B → 2, C → 1, D → 3
- 2A → 1, B → 3, C → 2, D → 4
- 3A → 2, B → 1, C → 3, D → 4
- 4A → 1, B → 2, C → 3, D → 4✓
Correct answer
A → 1, B → 2, C → 3, D → 4
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