Mathematics · Difference Equations
After eliminating the arbitrary constants A and B from yn = A ⋅ 2n + B ⋅ 3n, the corresponding difference equation is:
- 1yn+2 - 5yn+1 + 6yn = 0✓
- 2yn+2 - 6yn+1 + 5yn = 0
- 36yn+2 + 5yn+1 + yn = 0
- 46yn+2 - yn+1 + yn = 0
Correct answer
yn+2 - 5yn+1 + 6yn = 0
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