Physics · Moment of Inertia
According to the parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through its center of gravity IP is given by which of the following expressions? (Where A = area of the section, IG = moment of inertia of the section about an axis passing through its CG, and h = distance between the CG and the parallel axis.)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1IP = IG + Ah2✓
- 2IP = IG − Ah2
- 3IP = IG / Ah2
- 4IP = Ah2 / IG
Correct answer
IP = IG + Ah2
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Moment of Inertia MCQs →Want more practice questions on Moment of Inertia?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Moment of Inertia