Mathematics · Kinematics
A train moving at 60 miles per hour is brought to rest in 3 minutes with uniform retardation. Find this retardation and the distance the train travels before coming to rest. (Take 1 mile = 5280 feet)
- 1-22/90 ft/sec2, 3960 feet
- 2-22/45 ft/sec2, 3960 feet
- 3-44/45 ft/sec2, 7920 feet
- 4-22/45 ft/sec2, 7920 feet✓
Correct answer
-22/45 ft/sec2, 7920 feet
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